Software Development Tricky

Thursday, 27 April 2017

Find Second Highest Number in an Array


Sample Code:

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using System;
using System.Linq;
namespace Logical_Programs
{
    class _2ndLargestNumberInArray
    {
        static void Main()
        {
            int[] myArray = new int[] { 0, 48, 65, 10, 49, 3, 40 };
            Console.WriteLine("find 2nd height number in array");
            Console.WriteLine("**********************************");
            Console.WriteLine("First Approach: Using Foreach");
            Console.WriteLine("Result: {0}", get2ndHeightNumber_FirstApproach(myArray));
            Console.WriteLine("Second Approach: Using Linq Query");
            Console.WriteLine("Result: {0}", get2ndHeightNumber_SecondApproach(myArray));
            Console.WriteLine("**********************************");
            Console.WriteLine("Press any key to continue...");
            Console.ReadLine();
        }
        /// <summary>
        /// get 2nd height number with help of foreach
        /// </summary>
        /// <param name="myArray"></param>
        /// <returns></returns>
        public static int get2ndHeightNumber_FirstApproach(int[] myArray)
        {
            int largest = int.MinValue;
            int second = int.MinValue;
            foreach (int i in myArray)
            {
                if (i > largest)
                {
                    second = largest;
                    largest = i;
                }
                else if(i > second)
                {
                    second = i;
                }
            }
            return second;
        }
        /// <summary>
        /// get 2nd height number with help of linq query
        /// </summary>
        /// <param name="myArray"></param>
        /// <returns></returns>
        public static int get2ndHeightNumber_SecondApproach(int[] myArray)
        {
            int secondHighest = myArray.OrderByDescending(x => x).Distinct().Skip(1).First();
            return secondHighest;
        }
    }
}

Output:


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